U4L3 Solving Quadratic Equations quick check conexus answers
3 answers
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1. What is the solution of n² – 49 = 0? (1 point)
–7
7
±7
no solution
2. What is the solution of x² + 64 = 0? (1 point)
–5
8
±8
no solution
3. What is the side length of a square with an area of 144x²? (1 point)
12
12x
±12x
no solution
4. What is the value of b in the triangle shown below?
(Image: A right triangle is shown. The left leg equals 3 b. The lower leg equal b. The area of the triangle equals 24 square inches.) (1 point)
–4 in
4 in
±4 in
no solution
5. What is the value of z so that –9 and 9 are both solutions of x² + z = 103?
–22
3
22
184
–7
7
±7
no solution
2. What is the solution of x² + 64 = 0? (1 point)
–5
8
±8
no solution
3. What is the side length of a square with an area of 144x²? (1 point)
12
12x
±12x
no solution
4. What is the value of b in the triangle shown below?
(Image: A right triangle is shown. The left leg equals 3 b. The lower leg equal b. The area of the triangle equals 24 square inches.) (1 point)
–4 in
4 in
±4 in
no solution
5. What is the value of z so that –9 and 9 are both solutions of x² + z = 103?
–22
3
22
184
#1. (n-7)(n+7) = 0
#2. no real solutions. x^2+64 = (x+8i)(x-8i)
#3. √144x^2 = 12x
#4. 1/2 b(3b) = 24, so b^2 = 16, making b=4
#5. x^2 = 103-z
if 9 and -9 are solutions, then x^2=81
so 103-z = 81, making z = 22
#2. no real solutions. x^2+64 = (x+8i)(x-8i)
#3. √144x^2 = 12x
#4. 1/2 b(3b) = 24, so b^2 = 16, making b=4
#5. x^2 = 103-z
if 9 and -9 are solutions, then x^2=81
so 103-z = 81, making z = 22