Asked by Jane
Solving quadratic equations:
What is the value of "b" in the triangle where one part of the right angle is "3b" and the other part of the right angle is "b". The area inside is 24 in^2.
Please solve and explain. Thanks
What is the value of "b" in the triangle where one part of the right angle is "3b" and the other part of the right angle is "b". The area inside is 24 in^2.
Please solve and explain. Thanks
Answers
Answered by
Henry
3b/2 * b = 24 In^2
Multiply both sides by 2:
3b * b = 48
3b^2 = 48
b^2 = 16.
b = +-4 In.
Multiply both sides by 2:
3b * b = 48
3b^2 = 48
b^2 = 16.
b = +-4 In.
There are no AI answers yet. The ability to request AI answers is coming soon!