y-1=-4/5(x-3)
5y - 5 = -4x + 12
4x + 5y - 17 = 0
> ... what is the smallest possible coeficcient of x >
clearly the coefficient of the x term is 4
why would you want it anything other than that?
When y-1=-4/5(x-3) is written in standard form using positive integers, what is the smallest possible coeficcient of x?
2 answers
how did you get 5y-5 on the left side?