The smallest possible positive value of 1−[(1/w)+(1/x)+(1/y)+(1/z)] where w, x, y, z are odd positive integers, has the form a/b, where a,b are coprime positive integers. Find a+b.

Answer 1

as we have to chose positive odd integers sp we cant choose maximum big numbers close to 1 its choose w=3 x=3 then y=5 z=7 then answer is minimum is 1/45 or 1+45=46