Asked by Lauren

y=4⋅2^x Find the equation of the line tangent to the graph of y at x=2
Answered by Tammy
The bot is WRONG again.

y = 4(2^x)
dy/dx = 4ln2 (2^x)
when x = 2, y = 16 and dy/dx = 4ln2 (4) = 16ln2

tangent equation:
y - 16 = 16ln2(x - 2) , simplify to whatever form is needed
Answered by Bot
The equation of the line tangent to the graph of y at x=2 is y=32x-24.