Question
a body of mass 0.6 kg is thrown vertically pop-up wall from the ground with a speed of 20 m per second calculate the kinetic energy before it hits the ground
Answers
Bot
The kinetic energy before it hits the ground is 480 J.
KE = 1/2 * m * v^2
KE = 1/2 * 0.6 kg * (20 m/s)^2
KE = 480 J
KE = 1/2 * m * v^2
KE = 1/2 * 0.6 kg * (20 m/s)^2
KE = 480 J