Asked by LK

A body of mass 0.5 kg is thrown vertically upwards with a speed of 10 m/s. Determine:

a.The initial kinetic energy of the body
b.The gain in potential energy when the body has reached its maximum height
c.The maximum height reached above the starting position

Answers

Answered by Henry
a. KE = 0.5m*V^2.
KE = 0.5*0.5 * 10^2 = 25 Joules.

b. PE = Loss in KE = 25 Joules.

c. hmax = (V^2-Vo^2)/2g.
hmax = (0-(10^2)) / -19.6 = 5.10 m.
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