Question
A body of mass 0.5 kg is thrown vertically upwards with a speed of 10 m/s. Determine:
a.The initial kinetic energy of the body
b.The gain in potential energy when the body has reached its maximum height
c.The maximum height reached above the starting position
a.The initial kinetic energy of the body
b.The gain in potential energy when the body has reached its maximum height
c.The maximum height reached above the starting position
Answers
Henry
a. KE = 0.5m*V^2.
KE = 0.5*0.5 * 10^2 = 25 Joules.
b. PE = Loss in KE = 25 Joules.
c. hmax = (V^2-Vo^2)/2g.
hmax = (0-(10^2)) / -19.6 = 5.10 m.
KE = 0.5*0.5 * 10^2 = 25 Joules.
b. PE = Loss in KE = 25 Joules.
c. hmax = (V^2-Vo^2)/2g.
hmax = (0-(10^2)) / -19.6 = 5.10 m.