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How do you proove the identity
tanxsin2x = 2-2cos^2x
1 answer
tanx sin2x=2sinxcosx(sinx/cosx)=
2sin^2 x= 2*(1-cos^2 x)
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Verify tanxsin2x = 2-2cos^2x
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sin x(1 - 2 cos^2 x + cos^4 x) = sin^5 x 1-2cos^2 x looks like 2cos^2x-1 its just backwards. I am not sure
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the problem is
2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
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cosA= 5/9 find cos1/2A
are you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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