Asked by jessica
The following identity can be used to find Pythagorean triples, where the expressions x2−y2, 2xy, and x2+y2 represent the lengths of three sides of a right triangle; x and y are positive integers; and x>y.
(x2−y2)2+(2xy)2=(x2+y2)2
If the sides of a right triangle are 57, 176, and 185, what are the values of x and y?
Select two answers: one for x and one for y.
15
10
16
9
8
11
(x2−y2)2+(2xy)2=(x2+y2)2
If the sides of a right triangle are 57, 176, and 185, what are the values of x and y?
Select two answers: one for x and one for y.
15
10
16
9
8
11
Answers
Answered by
oobleck
so, you have
(x^2-y^2)^2 = 57^2
(2xy)^2 = 176^2
so,
x^4 - 2x^2y^2 + y^4 + 4x^2y^2 = 185^2
But that is
(x^2+y^2)^2 = 185^2
Now you have
x^2-y^2 = 57
x^2+y^2 = 185
adding, 2x^2 = 242
x^2 = 121
x = 11
now you can find y.
(x^2-y^2)^2 = 57^2
(2xy)^2 = 176^2
so,
x^4 - 2x^2y^2 + y^4 + 4x^2y^2 = 185^2
But that is
(x^2+y^2)^2 = 185^2
Now you have
x^2-y^2 = 57
x^2+y^2 = 185
adding, 2x^2 = 242
x^2 = 121
x = 11
now you can find y.
Answered by
Rolando Morales
kids
Answered by
Anonymous
this website sucks lol
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