Asked by arthur

Proove that:
a)2^(1/2) is not rational.
b) prove that 2^(1/3) is not rational.

I have managed to prove the first part, but i am stuck on the second can someone give me an hint please?

Answers

Answered by Reiny
assume 2^(1/2) is a rational number in the form a/b, where a/b is reduced to lowest terms

2^(1/3) = a/b
cube both sides
2= a^3/b^3
2b^2 = a^3
the left side of this equation is even
then the right side of the equation must be even
Properties of integers:
if you cube an even number the result is even
so a must be even.
Which means we could write a = 2k
and back in 2b^3 = a^3 , we can say
2b^3 = 8k^3
b^3= 4k^3
Now the right side is even, which means the LS is even and b itself must be even

so our original assumption that 2^(1/3) = a/b , where a/b is in lowest terms, led us to conclude that both a and b were even.
This is a contradiction, since a/b can be further reduced.
Thus our assumption that 2^(1/3) is rational MUST BE FALSE
Therefore 2^(1/3) is NOT rational

Note that this follows almost exactly what you must have done for the first question
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions