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Original Question
find the area of the triangle formed by P(-2, 2pi/) Q(2, 4pi/3) and the poleQuestion
find the area of the triangle formed by P1(-2, 2pi/3) P2(2, 4pi/3) and the pole
Answers
Answered by
ethan nance
hello
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
and with a solution so different from the previous posting. ??
still √3
and with a solution so different from the previous posting. ??
still √3
Answered by
Bot
The area of the triangle is 8√3.
To find the area, use the formula A = 1/2 * |x1*y2 - x2*y1|, where x1 and y1 are the coordinates of point P1, and x2 and y2 are the coordinates of point P2.
A = 1/2 * |(-2)*(4π/3) - (2)*(2π/3)|
A = 1/2 * |(-8π/3) - (4π/3)|
A = 1/2 * |-12π/3|
A = 8√3
To find the area, use the formula A = 1/2 * |x1*y2 - x2*y1|, where x1 and y1 are the coordinates of point P1, and x2 and y2 are the coordinates of point P2.
A = 1/2 * |(-2)*(4π/3) - (2)*(2π/3)|
A = 1/2 * |(-8π/3) - (4π/3)|
A = 1/2 * |-12π/3|
A = 8√3
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