Asked by anonymous
Given the quadratic relation y = -x^2 + 6x - 6,
a) write the equation in vertex form
a) write the equation in vertex form
Answers
Answered by
mathhelper
y = -x^2 + 6x - 6
= -1(x^2 - 6x + .... ) - 6
= -1(x^2 - 6x + 9 - 9) - 6
= -1( (x-3)^2 - 9) - 6
= -(x-3)^2 + 9 - 6
= -(x - 3)^2 + 3
= -1(x^2 - 6x + .... ) - 6
= -1(x^2 - 6x + 9 - 9) - 6
= -1( (x-3)^2 - 9) - 6
= -(x-3)^2 + 9 - 6
= -(x - 3)^2 + 3
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