Asked by Mai
The relation between the # of time in days, D, it takes for a planet to revolve around the Sun is related to the planer's average distance from the Sun, k, in millions of kilometres is defined by log D= 3/2logk-0.7 .
How much longer does it take Mars than
Venus to orbit the Sun if Mars is 207 million km and Venus is 108 million km away from the Sun?
The answer i got was originally 0.424.. but it seemed off to be so i tried it a different way and got 2.3 , can someone tell me which is correct?
How much longer does it take Mars than
Venus to orbit the Sun if Mars is 207 million km and Venus is 108 million km away from the Sun?
The answer i got was originally 0.424.. but it seemed off to be so i tried it a different way and got 2.3 , can someone tell me which is correct?
Answers
Answered by
Reiny
you will have to use brackets so I can tell what the order of operation is
The way you typed it it would be
D = (3/2)logk - 0.7
but I have a feeling it could be
D = 3/(2logk) - .07 or even
D = 3/(2logk - 0.7)
The way you typed it it would be
D = (3/2)logk - 0.7
but I have a feeling it could be
D = 3/(2logk) - .07 or even
D = 3/(2logk - 0.7)
Answered by
Mai
opps, im sorry.. its suppose to be D = (3/2)logk - 0.7
Answered by
Reiny
so for Mars k = 207 and
D = (3/2)log207 - .07 = 2.774
for Venus k = 108 and
D = (3/2)log108 - .7 = 2.350
the difference between these two times is .4238 days, which matches appr. your first answer.
D = (3/2)log207 - .07 = 2.774
for Venus k = 108 and
D = (3/2)log108 - .7 = 2.350
the difference between these two times is .4238 days, which matches appr. your first answer.
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