Asked by j
Calculate the cross sectional area intersected by a sphere ((𝑥 + 1)^2 + (𝑦 − 2)^2 + (𝑧 − 1)^2 = 25) and a plane z =4.
Answers
Answered by
mathhelper
plug in z = 4
(x+1)^2 + (y-2)^2 + 3^2 = 25
(x+1)^2 + (y-2)^2 = 16
so the radius is 4
area of circle = π r^2 = 16π units^2
(x+1)^2 + (y-2)^2 + 3^2 = 25
(x+1)^2 + (y-2)^2 = 16
so the radius is 4
area of circle = π r^2 = 16π units^2
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