Asked by Anon

A pipe has a cross sectional radius of 6.00 cm and is carrying water moving at .380 m/sec. If the pipe narrows to a radius of 3.50 cm, what will be the speed of the water in the narrow segment? What is the flow rate in each segment?

thank you!!!!!!!
Answered by bobpursley

lAW OF CONTINUITY:

area1*speed1=area2*speed2
speednarrow=PI(6^2)*.380/(.350^2)

volume flow rate=speed*area do that for both sides.
Answered by bobpursley
oops, add a PI in the denominator of the law of continuity, area=pI*radius^2
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