Asked by Rick
A wire with cross sectional area 1.00 cm2 stretches 0.500% of its length when it is stretched with a tension of 20.0 N. What is the Young's modulus of this wire?
Answers
Answered by
bobpursley
E= (force/area) /(dL/L)
= (20N/1E-4m^2)/(.005)
E= 20E4*2E2=40E6 N/m^2
Answered by
Damon
1 cm^2 = 10^-4 m^2
delta L = L F/(EA)
.005 = 20 /(E*10^-4)
E = 4*10^7 Pascals
Think material is like rubber or you have a typo.
delta L = L F/(EA)
.005 = 20 /(E*10^-4)
E = 4*10^7 Pascals
Think material is like rubber or you have a typo.
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