Asked by Shanell
A block of mass m1 = 16.4 kg is on a frictionless table to the left of a second block of mass m2 = 15.2 kg, attached by a horizontal string (see the figure below).
Two masses, m1 and m2, are placed on a horizontal surface such that they do not touch and m1 is to the left of m2. The left and right ends of a string are, respectively, attached to m1 and m2. A horizontal rightward arrow labeled vector F extends from m2.
(a)
If a horizontal force of 1.73 ✕ 102 N is exerted on the block m2 in the positive x-direction, use the system approach to find the acceleration (in m/s2) of the two blocks.
What is the tension (in N) in the string connecting the blocks?
Two masses, m1 and m2, are placed on a horizontal surface such that they do not touch and m1 is to the left of m2. The left and right ends of a string are, respectively, attached to m1 and m2. A horizontal rightward arrow labeled vector F extends from m2.
(a)
If a horizontal force of 1.73 ✕ 102 N is exerted on the block m2 in the positive x-direction, use the system approach to find the acceleration (in m/s2) of the two blocks.
What is the tension (in N) in the string connecting the blocks?
Answers
Answered by
Anonymous
1.73*10^2 = (16.4 +15.2) a
then
N = 16.4 a
then
N = 16.4 a
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