Asked by Akashdeep Singh
A block of mass m1 = 3.08 kg on a friction less plane inclined at angle θ = 32.3° is connected by a cord over a massless, frictionless pulley to a second block of mass m2 = 2.51 kg hanging vertically (see the figure). (a) What is the acceleration of the hanging block (choose the positive direction down)? (b) What is the tension in the cord?
Answers
Answered by
Damon
F = 2.51 (9.81) - 3.08 (9.81) sin 32.3
= 8.48 N
a = F/m = 8.48/(2.51+3.08)
2.51(9.81) - T = 2.51 a
= 8.48 N
a = F/m = 8.48/(2.51+3.08)
2.51(9.81) - T = 2.51 a
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