Asked by Em
A block with a mass of 0.357 kg is attached to a spring of spring constant 599 N/m. It is sitting at equilibrium. You then pull the block down 4.80 cm from equilibrium and let go. What is the amplitude of the oscillation?
I know A=D/F... I keep getting the wrong answer though. I even made sure to convert my answer. Please help!
Thanks
I know A=D/F... I keep getting the wrong answer though. I even made sure to convert my answer. Please help!
Thanks
Answers
Answered by
bobpursley
you are overthinking this.
Amplitude=4.8cm
Amplitude=4.8cm
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