Ask a New Question

Question

A pair of parallel metal plates has a potential difference of 5000 V across them.
The electric field strength between them is 400 kN C^−1
. Calculate:
a the separation between the plates
b the force on a dust particle between the plates which carries a charge of 1.6 × 10^−19 C.
3 years ago

Answers

Related Questions

The plates of a parallel plate capacitor each have an area of 0.40 m2 and are separated by a distanc... Two parallel plates, each with zero mass and an area of 10,000 cm2 are set 0.1 mm apart and the spac... Two parallel plates, separated by 10 mm, are charged to a potential difference of 50 V (that is, one... Two parallel plates are 4.85 cm apart. The bottom plate is charged positively and the top plate is c... a pair of parallel plates is charge by a 30.3V battery, if the field between the plates is 1050N/C h... A pair of parallel plates are charged with uniform charge densities of –32pC/m2 and +32pC/m2 . The d... two parallel plates are separated by a dielectric of thickness 2mm and a dielectric of constant 6.if... Two metal plates with the same dimension are soldered together face to face. The face of plate 1 th... Two large parallel metal plates are 3.0 cm apart. The magnitude of the electric field between them i... Two large parallel metal plates are 6.0 cm apart. The magnitude of the electric field between them i...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use