Question

Two parallel plates are charged to a potential difference of 10.0 volts. Determine the maximum speed of an electron that starts from rest at the negative plate and travels towards the positive plate.

Answer 1

kinetic energy gained = Qelectron * 10 volts

(1/2)(mass of electron) v^2 = that kinetic energy you just found

Answer 2

Thank you Damon! So I equal the KE formula to (-1.6 x 10^-19)(10) which is (-1.6 x 10^-18)?

Answer 3

yes