Asked by L@W

Two parallel plates are charged to a potential difference of 10.0 volts. Determine the maximum speed of an electron that starts from rest at the negative plate and travels towards the positive plate.
Answered by Damon
kinetic energy gained = Qelectron * 10 volts

(1/2)(mass of electron) v^2 = that kinetic energy you just found

Answered by L@W
Thank you Damon! So I equal the KE formula to (-1.6 x 10^-19)(10) which is (-1.6 x 10^-18)?
Answered by Damon
yes
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