Asked by pakilina
The charged plates of a parallel plate capacitor each have a charge density of sigma C/m^2. Using Gauss's law, compute the electric field between the plates.
Answers
Answered by
drwls
Gauss' law says that
E*Area = sigma*Area/epsilon
or
E = sigma/epsilon
where epsilon is the permittitivy.
The answer will depend upon the dielectric constant of the material between the plates.
If there is a vacuum or air between the parallel plates,
epsilon = epsilonzero = 8.85*10^-12 farad/meter
E*Area = sigma*Area/epsilon
or
E = sigma/epsilon
where epsilon is the permittitivy.
The answer will depend upon the dielectric constant of the material between the plates.
If there is a vacuum or air between the parallel plates,
epsilon = epsilonzero = 8.85*10^-12 farad/meter
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