Question

a pair of parallel plates is charge by a 30.3V battery, if the field between the plates is 1050N/C how far apart are the plates? answer in meters

Answer 1

1050 N/C field strength means the same thing as 1050 Volts per meter voltage gradient between the plates.

1050*d = 30.3
Solve for plate separation d.
d = 0.0289 m