Asked by Anonymous
a 0.20 kg mass is attached to the end of a spring causes it to stretch from 25cm to 95cm. what is the spring constant?
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Answered by
Anonymous
F = m g = 0.20 * 9.81 = 1.96 Newtons (assuming on earth)
x = extension of spring = (1/100)(95 - 25) = 0.700 meters
k = F/x = 1.96 N/0.7 meter = 2.8 Newtons / meter
x = extension of spring = (1/100)(95 - 25) = 0.700 meters
k = F/x = 1.96 N/0.7 meter = 2.8 Newtons / meter
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