Asked by Anna
A 2.0 kg mass is attached to a string that is 1.0 m long and moves in a horizontal circle at a rate of 4.0 revolutions per second.
a) What is the centripetal acceleration of the mass?
I converted 4 rev/s to 25.13 rad/s and used the equation: a=rw^2 to get 632 m/s^2
b) What is the tension in the string?
The answer sheet says 1250 N but I have no idea how to get there.
a) What is the centripetal acceleration of the mass?
I converted 4 rev/s to 25.13 rad/s and used the equation: a=rw^2 to get 632 m/s^2
b) What is the tension in the string?
The answer sheet says 1250 N but I have no idea how to get there.
Answers
Answered by
Damon
Your problem only has two significant figures accuracy
to two significant figures w = 25
so
r w^2 = 625
F = m a
F = 2 kg * 625 m/s^2 = 1250 N
to two significant figures w = 25
so
r w^2 = 625
F = m a
F = 2 kg * 625 m/s^2 = 1250 N
Answered by
Anna
Thanks. I didn't realize f=ma could be used because of gravity's acceleration.
Answered by
Damon
Gravity is not in this because it says in a HORIZONTAL circle (it must be on a table top or something but 625 is much bigger than g anyway))
Answered by
Anna
Okay, I understand now. Thank you.
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