Asked by kelsi
A mass of 0.52 kg attached to a vertical spring
stretches the spring 39 cm from its original
equilibrium position.
The acceleration of gravity is 9.81 m/s2 .
What is the spring constant?
stretches the spring 39 cm from its original
equilibrium position.
The acceleration of gravity is 9.81 m/s2 .
What is the spring constant?
Answers
Answered by
bobpursley
force=kx
.52g=k(.39)
solve for k
.52g=k(.39)
solve for k
Answered by
Jen
13.1 N/m
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