Asked by Jonathan audu
Find the equation of a straight line passing through(-9,5) and inclined at an angle of 120 degreen with the positive direction o3 x-axis.
Answers
Answered by
oobleck
the slope of the line is tan120° = -√3
Now you have a point and a slope, so
y-5 = √3(x+9)
Now you have a point and a slope, so
y-5 = √3(x+9)
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