Asked by Anonymous
Find the equation of a straight line which is equidistant from the points (2,3) and (6,1) expressing it in the form ax+by=c
Answers
Answered by
oobleck
the line through those two points has slope -1/2
the line containing all points equidistant from those two points will be the perpendicular bisector, which has slope 2
The midpoint is (4,2) so we want the line with equation
y-2 = 2(x-4)
y-2 = 2x-8
2x-y = 6
the line containing all points equidistant from those two points will be the perpendicular bisector, which has slope 2
The midpoint is (4,2) so we want the line with equation
y-2 = 2(x-4)
y-2 = 2x-8
2x-y = 6
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.