Asked by Ozy
A number of two digits is such that twice the tense digit is 8 less than seven times the unit digit,when the digits is reversed,the numbers are increased by 9.what are the numbers?
Answers
Answered by
oobleck
tens' digit, not tense digit ...
so, we have
t = 7u-8
10u+t = 10t+u + 9
recall that if reversing the digits increases the number by 9, the two digits are consecutive numbers.
so, we have
t = 7u-8
10u+t = 10t+u + 9
recall that if reversing the digits increases the number by 9, the two digits are consecutive numbers.
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