Asked by Zulaiykherh
A number of two digits is such that twice the ten digits is 8 less than seven times the unit digit. When the digits are reversed, the number is decreased by 9. What is the number?
Answers
Answered by
Reiny
let the tens digit be x, and the unit digit be y
So the number is 10x + y,
the number reversed is 10y + x
10x+y - (10y+x) = 9
9x - 9y = 9
x - y = 1 or x = y+1 **
2x = 7y-8
sub in **
2(y+1) = 7y - 8
2y + 2 = 7y - 8
-5y = -10
y = 2
The number is 32
check:
the number reversed is 23, which is 9 less than 32.
Twice the ten digit is 6
7 times the unit digit = 14, which is 8 less than 6
My answer is correct.
So the number is 10x + y,
the number reversed is 10y + x
10x+y - (10y+x) = 9
9x - 9y = 9
x - y = 1 or x = y+1 **
2x = 7y-8
sub in **
2(y+1) = 7y - 8
2y + 2 = 7y - 8
-5y = -10
y = 2
The number is 32
check:
the number reversed is 23, which is 9 less than 32.
Twice the ten digit is 6
7 times the unit digit = 14, which is 8 less than 6
My answer is correct.
Answered by
Zulaiykherh
Pls how did you get 32 as the number
Answered by
Hamzat
Superb
Answered by
Prosper
Thanks,but why is it 10x+y and not x+y
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