Asked by Michelle
What is the antiderivative of this?
What is the antiderivative of x/((16+x^2)^(1/2))?
(x / the square root of (16 + x^2))?
What method did you use? Substitution, etc..?
Thanks!
What is the antiderivative of x/((16+x^2)^(1/2))?
(x / the square root of (16 + x^2))?
What method did you use? Substitution, etc..?
Thanks!
Answers
Answered by
drwls
Let 16 + x^2 = u
2x dx = du
Your integral becomes the integral of
(1/2) u^-1/2 du
which is
u^1/2 = sqrt(16 + x^2)
2x dx = du
Your integral becomes the integral of
(1/2) u^-1/2 du
which is
u^1/2 = sqrt(16 + x^2)
Answered by
manny
Find the most general antiderivative of the function. (Check your answer by differentiation. Use C for the constant of the antiderivative.)
f(x) = (x + 3)(5x − 1)
f(x) = (x + 3)(5x − 1)
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