Given that the antiderivative of f of x equals 1 divided by x is F(x) = Ln|x| + C, evaluate the integral from 1 to 2 of the 1 divided by x, dx.

you have the function. Use it.

To evaluate the integral from 1 to 2 of 1/x, you can use the antiderivative property of definite integrals. According to the given information, the antiderivative of 1/x is F(x) = ln|x| + C.

To find the definite integral from 1 to 2, you need to evaluate F(x) at the upper limit (2) and lower limit (1), and then subtract the result at the lower limit from the result at the upper limit.

So, evaluate F(2) and F(1):
F(2) = ln|2| + C = ln(2) + C
F(1) = ln|1| + C = ln(1) + C = 0 + C = C

Now subtract the result at the lower limit from the result at the upper limit:
∫(1 to 2) 1/x dx = F(2) - F(1) = (ln(2) + C) - C = ln(2)

Therefore, the evaluation of the integral from 1 to 2 of 1/x, dx, is ln(2).