Given that the antiderivative of f(x) = e4x is F(x) = 1/4e^4x+C, evaluate the integral from 0 to 2 of e^4x, dx.

e^8
1/4(1-e^8)
1/4(e^8-1)
1/4e^8 (MY ANNSWER)

1 answer

∫[0,2] e^(4x) dx
= 1/4 e^(4x) + C [0,2]
= (1/4 e^8 + C)-(1/4 e^0 + C)
= 1/4 (e^8 - 1)

remember that e^0=1, not 0.