Asked by Jess
Given that the antiderivative of f(x) = e4x is F(x) = 1/4e^4x+C, evaluate the integral from 0 to 2 of e^4x, dx.
e^8
1/4(1-e^8)
1/4(e^8-1)
1/4e^8 (MY ANNSWER)
e^8
1/4(1-e^8)
1/4(e^8-1)
1/4e^8 (MY ANNSWER)
Answers
Answered by
Steve
∫[0,2] e^(4x) dx
= 1/4 e^(4x) + C [0,2]
= (1/4 e^8 + C)-(1/4 e^0 + C)
= 1/4 (e^8 - 1)
remember that e^0=1, not 0.
= 1/4 e^(4x) + C [0,2]
= (1/4 e^8 + C)-(1/4 e^0 + C)
= 1/4 (e^8 - 1)
remember that e^0=1, not 0.
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