Asked by Flanckline
Solve for x in the equition 27^x-1 ×3^x+1=729
Answers
Answered by
mathhelper
assuming you meant:
27^(x-1) ×3^(x+1)=729
3^(3x-3) * 3(x+1) = 3^6
3^(4x - 2) = 3^6
4x-2 = 6
x = 2
27^(x-1) ×3^(x+1)=729
3^(3x-3) * 3(x+1) = 3^6
3^(4x - 2) = 3^6
4x-2 = 6
x = 2
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