Ask a New Question

Asked by Anonymous

(6-a),6,(7-5a) are consecutive terms of GP with the common ratio r > 0 .Find the value of a???
3 years ago

Answers

Answered by mathhelper
6/(6-a) = (7-5a)/6
42 - 30a -7a + 5a^2 = 36
5a^2 - 37a + 6 = 0

solve using the quadratic equation, it does not factor
3 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

If 3,p,q,24 are consecutive term of an exponential sequence, find the value of p and q and hence the... The sum of four consecutive even integers is the same as the least of the integers. Find the integer... The sum of four consecutive even integers is the same as the least of the integers. Find the integer... The sum of three consecutive positive integers is 315. Find the numbers. ( Hint: x, x+1, x + 2 ) The sum of three consecutive natural numbers is 963, find the numbers. (A) First, write out an eq... The sum of three consecutive natural numbers is 966. Find the numbers. The sum of three consecutive odd numbers is 615? Find the numbers. the sum of three consecutive multiple of 7 is 777. find these multiple The sum of three consecutive even integers is 54. What is the middle integer . Between what two consecutive integers on the number line is the graph of the sum √30 + √50 located?...
Submit Your Answer

Question

(6-a),6,(7-5a) are consecutive terms of GP with the common ratio r > 0 .Find the value of a???

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use