Asked by shehzad
                the sum of three consecutive multiple of 7 is 777. find these multiple
            
            
        Answers
                    Answered by
            Bosnian
            
    first number = 7 n
second number = 7 n + 7
third number = 7 n + 14
7 n + 7 n + 7 + 7 n + 14 = 777
21 n + 21 = 777 Subtact 21 to both sides
21 n + 21 - 21 = 777 - 21
21 n = 756 Divide both sides by 21
n = 756 / 21 = 36
first number = 7 n = 7 * 36 = 252
second number = 7 n + 7 = 7 * 36 + 7 = 252 + 7 = 259
third number = 7 n + 14 = 7 * 36 + 14 = 252 + 14 = 266
252 + 259 + 266 = 777
    
second number = 7 n + 7
third number = 7 n + 14
7 n + 7 n + 7 + 7 n + 14 = 777
21 n + 21 = 777 Subtact 21 to both sides
21 n + 21 - 21 = 777 - 21
21 n = 756 Divide both sides by 21
n = 756 / 21 = 36
first number = 7 n = 7 * 36 = 252
second number = 7 n + 7 = 7 * 36 + 7 = 252 + 7 = 259
third number = 7 n + 14 = 7 * 36 + 14 = 252 + 14 = 266
252 + 259 + 266 = 777
                    Answered by
            chanti
            
    the average of 5 consecutive multiples of 9 is 54.what is the least but one number?
    
                    Answered by
            Anonymous
            
    x, x+7, x+14=777
3x+21 = 777
3x = 777-21 = 756
3x=756
x=756/3
x=253
therefore 1st no = 253+7 = 259
2nd no= 253+14 = 266 [ans]
    
3x+21 = 777
3x = 777-21 = 756
3x=756
x=756/3
x=253
therefore 1st no = 253+7 = 259
2nd no= 253+14 = 266 [ans]
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