Asked by Anonymous
In the quadrilateral abcd below,ab=3cm,bc=4cm,cd=12cm and angle abc=90degree and angle acd=90degree.Calculate the perimeter and area of abcd
Answers
Answered by
oobleck
∆ABC is a 3-4-5 right triangle
∆ACD is a 5-12-13 right triangle
That gives you
P = 3+4+12+13 = 32
A = 3*4/2 + 5*12/2 = 36
∆ACD is a 5-12-13 right triangle
That gives you
P = 3+4+12+13 = 32
A = 3*4/2 + 5*12/2 = 36
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