Asked by Anonymous
Find two consecutive odd integers whose products is 783.let x be the first odd integer. Write an expression for the second odd integer.
Answers
Answered by
mathhelper
first odd integer --- x
2nd odd integer ---- x+2
x(x+2) = 783
x^2 + 2x + 1 = 783 + 1 , I completed the square
(x+1)^2 = 784
x+1 = 28
x = 27
the two odd integers are 27 and 29
I just realized I answered your question in my second line
2nd odd integer ---- x+2
x(x+2) = 783
x^2 + 2x + 1 = 783 + 1 , I completed the square
(x+1)^2 = 784
x+1 = 28
x = 27
the two odd integers are 27 and 29
I just realized I answered your question in my second line
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