Asked by Andrew
Find two consecutive odd integers such that the square of the larger is one less than twice the square of the smaller.
Answers
Answered by
Ms. Sue
5 and 7
Check -- do those numbers work?
Check -- do those numbers work?
Answered by
Steve
(n+2)^2 = 2n^2 - 1
You might think that it would be possible for n to be even, but since the right side must be odd, so must n^2 be odd, and thus any solutions you find will be odd.
You might think that it would be possible for n to be even, but since the right side must be odd, so must n^2 be odd, and thus any solutions you find will be odd.
Answered by
andres
Find two consecutive even integers such that the sum of the larger and twice the smaller is 124.