Asked by Andrew
                Find two consecutive odd integers such that the square of the larger is one less than twice the square of the smaller. 
            
            
        Answers
                    Answered by
            Ms. Sue
            
    5 and 7
Check -- do those numbers work?
    
Check -- do those numbers work?
                    Answered by
            Steve
            
    (n+2)^2 = 2n^2 - 1
You might think that it would be possible for n to be even, but since the right side must be odd, so must n^2 be odd, and thus any solutions you find will be odd.
    
You might think that it would be possible for n to be even, but since the right side must be odd, so must n^2 be odd, and thus any solutions you find will be odd.
                    Answered by
            andres
            
    Find two consecutive even integers such that the sum of the larger and twice the smaller is 124.
    
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