Asked by Simi
A streched spring store an energy of 25j when it is extended by 6.7 ×10-²m. Calculate its force constant
Answers
Answered by
oobleck
F = kx
E = 1/2 kx^2 = 1/2 Fx so
1/2 F * 0.067 = 25
F = 50/0.067 = 750
k = 750/0.067 = 1125
E = 1/2 kx^2 = 1/2 Fx so
1/2 F * 0.067 = 25
F = 50/0.067 = 750
k = 750/0.067 = 1125
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