Asked by Jamiu
A spring is streched 40mm by a force of 15 newton, what is the work done.
Answers
Answered by
oobleck
F = kx, so k = F/x
work = 1/2 kx^2 = 1/2 Fx = 1/2 * 15 * 0.040 = ____ J
work = 1/2 kx^2 = 1/2 Fx = 1/2 * 15 * 0.040 = ____ J
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