Asked by Ntsako
Find the center and radius of the circle with equation x
2 + y
2 − 6x + 10y = 0
2 + y
2 − 6x + 10y = 0
Answers
Answered by
R_scott
x^2 + y^2 - 6x + 10y = 0
completing the squares
... x^2 - 6x + (-6/2)^2 + y^2 + 10y + (10/2)^2 = (-6/2)^2 + (10/2)^2
(x - 3)^2 + (y + 5)^2 = 9 + 25 = 34
center ... (3 , -5)
radius ... √34
completing the squares
... x^2 - 6x + (-6/2)^2 + y^2 + 10y + (10/2)^2 = (-6/2)^2 + (10/2)^2
(x - 3)^2 + (y + 5)^2 = 9 + 25 = 34
center ... (3 , -5)
radius ... √34
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