Asked by Jen
find the center and radius of a circle given the equation in general form
x^2+y^2+4x-6y+2=0.
center: ?
radius: ?
x^2+y^2+4x-6y+2=0.
center: ?
radius: ?
Answers
Answered by
Ms. Sue
Please use the same name for all of your posts.
By using different names, you're usurping names that are already used by other students.
By using different names, you're usurping names that are already used by other students.
Answered by
Jen
I am not sure what you're talking about.
Answered by
Ms. Sue
Meghan, John, and Jen all have the same ip address, a computer in St. Louis, Missouri.
Answered by
drwls
Rewrite the equation in the form
(x + 2)^2 + (y - 3)^3 = 11
This shows that it is a circle centered at x = -2, y = 3.
See of you can guess the radius, from the constant term on the right.
(x + 2)^2 + (y - 3)^3 = 11
This shows that it is a circle centered at x = -2, y = 3.
See of you can guess the radius, from the constant term on the right.
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