Question

Find the radius and the center of the circular section of the sphere |r| = 17 cut off by the plane r·(i+2j+2k) = 24. Solution

Answer 1

what is the normal to the plane that passes through (0,0,0)? If the distance from the plane to the origin is d, then

d^2+r^2 = 17^2

Answer 2

c) Find the radius and the center of the circular section of the sphere |r| = 17 cut off by the plane r·(i+2j+2k) = 24.