Asked by Mustapha
A number of 2 digit is increased by 9 when the digits are reversed, the sum of the digit is 5. Find the number
Answers
Answered by
mathhelper
in the original, let the unit digit be x, and the tens digit by y
x + y = 5 , (we can figure it out from here)
original number: 10y+x
number reversed: 10x+y
10x+y - (10y+x) = 9
9x - 9y = 9, or
x - y = 1
add this to x+y=5
2x = 6
x = 3, then y = 2
the original number was 23
(check: reversed would be 32, which is 9 more than the original)
x + y = 5 , (we can figure it out from here)
original number: 10y+x
number reversed: 10x+y
10x+y - (10y+x) = 9
9x - 9y = 9, or
x - y = 1
add this to x+y=5
2x = 6
x = 3, then y = 2
the original number was 23
(check: reversed would be 32, which is 9 more than the original)
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