Asked by MERCY
A car accelerates for 10sec to reaches a speed of 20mis it continue with uniform velocity for further 20sec&then decelerates so that it stops in 20sec calculates (a)acceleration (b)retardation (c)total distance covered.
Answers
Answered by
oobleck
(a) (20m/s) / (10s) = 2 m/s^2
(b) (-20m/s) / (20s) = -1 m/s^2
(c) (1/2 * 2 * 10^2) + 20*20 + (20*20 - 1/2 * 1 * 20^2) = 700 m
(b) (-20m/s) / (20s) = -1 m/s^2
(c) (1/2 * 2 * 10^2) + 20*20 + (20*20 - 1/2 * 1 * 20^2) = 700 m
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