Asked by Tyler
A car accelerates from 12m/s to 25m/s in 6.0s. What is its uniform acceleration? How far did it travel in this time?
Answers
Answered by
Damon
acceleration = change in velocity/change in time
= 13/6 = 2.17 m/s^2
d = 0 + Vi t + (1/2) a t^2
= 12 (6) + 1.09 (36)
= 111 meters
another way is that if acceleration is constant, use average velocity
(12+25)/2 = 18.5 m/s
18.5 * 6 = 111 meters sure enough
= 13/6 = 2.17 m/s^2
d = 0 + Vi t + (1/2) a t^2
= 12 (6) + 1.09 (36)
= 111 meters
another way is that if acceleration is constant, use average velocity
(12+25)/2 = 18.5 m/s
18.5 * 6 = 111 meters sure enough
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