Asked by su_pona
A bus accelerates at 1.4 m/s2 from rest for 14 s. It then travels at constant speed for 23 s, after which it slows to a stop with an acceleration of magnitude 1.3 m/s2.
Answers
Answered by
Henry
a. V = a*t = 1.4 * 14 = 19.6 m/s.
d = 0.5a*t^2 + V*t2 + (Vf-V)/2a
b. d = 0.5*1.4*14^2 + 19.6*23 + (0-(19.6^2)/-2.6 = 137.2 + 450.8 + 147.8
= 736 m.
d = 0.5a*t^2 + V*t2 + (Vf-V)/2a
b. d = 0.5*1.4*14^2 + 19.6*23 + (0-(19.6^2)/-2.6 = 137.2 + 450.8 + 147.8
= 736 m.
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