Question

If the density of pure acetic acid is 1.005g cm, what is its molarity?

Answer 1

You need to learn the difference between cm and cc or cm^3. cm is a distance. cc is a volume. 1 cc = 1 mL also.
density acetic acid = grams/mL = 1.005 g/cc = 1.005 g/mL.
mass of 1 L of this acid = 1.005 g/mL x 1000 mL = 1005 g.
How many moles is that? moles = g/molar mass = 1005/60 = ?
Then M = moles/L