Question

If the density of pure acetic acid is 1.005g/cm, what is it molarity

Answer 1

I expect you meant 1.00g g/cc. You will have 1.005 g/cc x 1000 cc = 1005 g acetic acid/L
mols acetic acid 1005/molar mass = 1005/60 = ?
So ?/L = ?M

Answer 2

16.75moles

Answer 3

Density= 1.005g/cm
10cm=1dm
100cm^2=1dm^2
1000cm^3=1dm^3
=({1.005g/1000}dm)^3=(0.001005dm)^3
=1.015075125*10^-9dm^3
Mass = 1.005g
Volume= 1cm
To convert to dm3
1000cm^3=1dm^3
=(1/1000)dm^3
=0.001dm^3
Molar mass of acetic acid(CH3COOH)= ((12*1)+(1*3)+(12*1)+(16*1)+(16*1)+(1*1))
=(12+3+12+16+16+1)g/mol
=60g/mol
Molarity=mole/volume
Mole= mass/molar mass
=1.005g/60g/mol
=0.01675mol
Recall that we are to get molarity
Molarity= 0.1675mol/0.001dm^3
Molarity =16.75moldm^-3